My confusion for lecture three is how the current divider law works with more than two resistors in parallel, the opposite R value going in the numerator wouldn't make sense in these cases. Is it even possible to apply the law with more than two resistors?
What I do with more than 3 branches: to find the current in branch #1, I combine the resistors in the other branches. Then apply the current divider rule to find the current in branch #1 and the combined parallel resistance of the other branches that have been combined into one resistance.
With Lecture two, would we be able to do an example in class reviewing how to identify and count nodes? This topic was touched on in lecture two at around 31:00, but I had trouble following on the powerpoint.
Pierce - did the in-class work help with node counting? If not, I can help again in class on Friday - just please remind me to help. Or pop by my office. I have candy
Again there's no post for lecture comments!!
ReplyDeleteMy confusion for lecture three is how the current divider law works with more than two resistors in parallel, the opposite R value going in the numerator wouldn't make sense in these cases. Is it even possible to apply the law with more than two resistors?
As stated in class, there is not an assigned blog.
DeleteWhat I do with more than 3 branches: to find the current in branch #1, I combine the resistors in the other branches. Then apply the current divider rule to find the current in branch #1 and the combined parallel resistance of the other branches that have been combined into one resistance.
DeleteWith Lecture two, would we be able to do an example in class reviewing how to identify and count nodes? This topic was touched on in lecture two at around 31:00, but I had trouble following on the powerpoint.
ReplyDeletePierce - did the in-class work help with node counting? If not, I can help again in class on Friday - just please remind me to help. Or pop by my office. I have candy
ReplyDelete